An Aeroplane has four emergency exits. In an emergency it requires 8 seconds per passenger to evacuate the plane, if the hand baggage is not carried by the passenger. How long will it take to eliminate 53 passengers in an emergency?
Answers
Answered by
18
the answer is 53×8=424second
so for 53 passengers it will take 424÷60=7.067minute
so for 53 passengers it will take 424÷60=7.067minute
Answered by
10
Answer:
7 min 4 sec
Step-by-step explanation:
time taken for 1 passenger to evacuate = 8 seconds
time taken for 53 passenger to evacuate = 8*53 seconds
=424 seconds
= 7 minute 4 seconds
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