An aeroplane is at an altitude of 300m observes an angle of depression of opposite points on the two banks of a river to be 45 and 60. Find width of river
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Hey!
Here's your answer>>>>>>
In ∆ABC
AC/BC=TAN45°
300/BC=1
300=BC (1)
IN ∆ACD
AC/CD=TAN60°
300/CD=√3
300/√3=CD
BY RATIONALISING
300×√3/√3×√3=CD
300√3/3=CD
100√3=CD (2)
WIDTH OF RIVER=BC+CD
WIDTH OF RIVER=300+100√3 (FROM EQUATION 1 AND2)
WIDTH OF RIVER=100(3+√3)m
This is the answer of your question Hope it helps...... :-)
Please mark it as brainliest...................
Here's your answer>>>>>>
In ∆ABC
AC/BC=TAN45°
300/BC=1
300=BC (1)
IN ∆ACD
AC/CD=TAN60°
300/CD=√3
300/√3=CD
BY RATIONALISING
300×√3/√3×√3=CD
300√3/3=CD
100√3=CD (2)
WIDTH OF RIVER=BC+CD
WIDTH OF RIVER=300+100√3 (FROM EQUATION 1 AND2)
WIDTH OF RIVER=100(3+√3)m
This is the answer of your question Hope it helps...... :-)
Please mark it as brainliest...................
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