An aeroplane is flying at a height of 300 above the ground. Flying at this
height, the angles of depression from the aeroplane of two points on both
banks of a river in opposite directions are 45° and 60° respectively. Find the
width of the river.
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Answer:
Let A be the aeroplane BD is the length of the river
tan45o =(AC/BC)
1= 300/BB
BC=300m
tan60o = (AC/CD)
root3 = 300/CD
CD=( 300/root 3)×(root 3/root 3)
=(300 root3)/root 3
=100root3
=1.732×100=173.2
width of river =BC+CD=300+173.2=473.2m
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