Physics, asked by Agent807, 6 months ago

An aeroplane is flying at a height of 3000 m above the ground level. If the angle subtended at ground observation point by the aeroplane position 12 s apart is 30°, what is the speed of the aeroplane?​

Answers

Answered by Nandani182403
1

Answer:

right angled triangle OAB, tan30

= h/x

We get x= h/tan30°

= 3000√3

=5190

Time taken t=12

Thus speed of the aircraft v= x/t

=5190/12

= 432.5 m/s

Similar questions