an aeroplane is flying at a height of 3000m an observer find the angle of elevation to be 60 degree and after 6sec it changes to 45 degree.what is the speed of the areoplane??
Answers
Answer:211.3 m/s
Step-by-step explanation:
Aqa
Answer:
Step-by-step explanation:
This question tests on the knowledge of trigonometric ratios.
The height above the ground where the plane is, the distance from the observer to just below the plane and the angle of elevation forms a right angled triangle.
When the angle of elevation shifts two right angled triangles are formed having a common height.
To get the distance moved by the train in 6 seconds we need to get the difference in lengths of the two bases of the right angled triangles formed by the motion.
We will use Tan:
Tan theta = opposite / adjacent.
The lengths are :
3000/Tan 45 = 3512.55 m
3000/Tan 60 = 2179.63
The difference gives = 3512.55 - 2179.33 = 1332.92 m
Speed = Distance / time
= 1332.92/6 = 222.15 m/s