Question

An aeroplane is flying horizontally at a height of 500 m with a velocity of 72 km h-over a flood affected
area. Food packets are to be dropped for the people standing at a particular place on th ground. At what
horizontal distance from that place should the food packets be released from the plane so as to reach the intended place.​

Answer 1

Answer:

When the food packets are released from the plane, it would have initial velosity same as the velosity of plane.

Motion of the body would be in two dimensions. In the vertical direction due to gravity and in the horizontal direction due to its initial velosity.

Initial velosity in the horizontal direction = ux = 72 km/hr

                                                               = 20 m/s

Initial velosity in the vertical direction is =uy = 0 m/s

Let's assume there is no effect of wind and air drag force.

Now, considering the vertical motion alone,

Time taken by the food packet to reach the ground is given by,

(Taking g = 10 m/s)

In the horizontal direction the packet is moving with uniform velocity. Hence, the acceleration is zero in horizontal direction.

Let X be the horizontal distance travelled by the packet in time t = 10 sec to reach the ground.

Thus, the food packets should be released from the distance 200 m to reach the intended place.

Answer 2

Answer:

200 m

Explanation:

Hi Friend!

When ever you are facing a Physics problem, first take up notes about the problem.

Notes:

1.) No force is acting in x-direction

2.) Object will move with constant velocity in x-direction

Okay, now lets solve the problem:

Lets say the plane is at a distance 's' from the place when dropping the package.

To reach the ground, time taken by packet:

s=500m , u=0 , a = 10 m/s^2

500 = 1/2 x 10 x t^2 ==========> t = 10 s

s = vt , v = 72kmph = 72 x 5 / 18 m/s = 20 m/s

s = 20 x 10 = 200 m

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