Question

An aeroplane is flying horizontally at height of 490 m above a point P on ground and a packet is to be dropped from it, which should reach at a point Q on ground which is 1600m away from point P. What should be the speed of plane at the time of release of packet? (g 9.8 ms2)​

Answer 1

Answer:

giving : height of flying airoplane=490=s

Explanation:

velocity of airoplane =150m/s

eq of motion = s=ut + 1/2 at²

u=0 g=9.8m/s

=490=1/2×9.8×t²=+2×490/9.8=t=10

horizontal distance covered in 10s

distance=150×10=1500m

(speed=distance /time)

=1500m