Question

an aeroplane is flying horizontally at height of 490m with a velocity of 360km/h. A bag containing ration is to be dropped to the jawans on the ground. How far from them should the bag be released, so that it falls directly over them​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Distance=1\:km}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Height(h) = 490 \: m \\ \\ \tt: \implies Initial \: velocity( v_{x}) = 360 \: km/h \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Distance (AB) =?$

• According to given question :

$\tt \circ \: v_{x} = 360 \times \frac{5}{18} = 100 \: m/s\\ \\ \tt \circ \: v_{y} = 0 \: m/s \\ \\ \tt \circ \: Acceleration = 9.8 \: {m/s}^{2} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies s = ut + \frac{1}{2} {at}^{2} \\ \\ \tt: \implies h = v_{y} t+ \frac{1}{2} a {t}^{2} \\ \\ \tt: \implies 490 = 0 \times t + \frac{1}{2} \times 9.8 \times {t}^{2} \\ \\ \tt: \implies \frac{490 \times 2}{9.8} = {t}^{2} \\ \\ \tt: \implies t = \sqrt{100} \\ \\ \green{\tt: \implies t = 10 \: sec} \\ \\ \bold{For \: distance \:AB :} \\ \tt: \implies AB = v_{x}t \\ \\ \tt: \implies AB = 100 \times 10 \\ \\ \green{\tt: \implies AB= 1000 \: m = 1 \: km}$

Answer 2

Explanation:

व्हाई इज इक्वल टू 5 सेंटीमीटर इज इक्वल टू थ्री सिक्सटी किलोमीटर जीव इक्वल टू 9.8 मीटर किलोमीटर