an aeroplane is flying horizontally with a velocity 720km/h at a height of 2000m.when it is verticallly at a point A on the ground, a bomb is released from it. the bomb strikes the ground at point B. the distance AB is
a.1km b.2km c.3km d.4km
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Answer:
y=ut+1/2gt^2
2000=+1/2×10×t^2
t=20
a=720-0/20
a=36
(720)^2-0=2×36×s
s=7200m
shwetabathina:
what is the correct option
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