Question

An aeroplane is flying horizontally with a velocity of 216 km / hr at a height of 1960 m. when it is vertically above a point ‘a' on the ground, a bomb is released from it. the bomb strikes the ground at point ‘b'. the distance ab is

Answer 1

heyy user ur answer.....

When the bomb is dropped, it will have an initial horizontal velocity which is equal to the speed of the aeroplane. So the bomb fall and travel forward too.
initial horizontal velocity, = 216 km/h=216×5/18=60 m/s
initial vertical velocity, = 0height, h = 1960mtime taken to fall = t
h=ut+1/2×gt^2........................g=9.8

1960=4.9t^2

t=√400=20sec

so, AB=ux×t=60×20=1200m

..i hope it will help u..................@kundan

Answer 2

When the bomb is dropped, it will have an initial horizontal velocity which is equal to the speed of the aeroplane. So the bomb fall and travel forward too

now

according to question

Initial Horizontal velocity = Vx = 216km/h
= 216×5/18 m/s
= 60 m/s

Initial vertical velocity = Vy = 0

Hight = h = 1960m

time time to fall = t

we know that

h = Vyt + 1/2gt2

1960 = 0 + 1/2×9.8×t2

1960 = 4.9×t2

t2 = 1960/4.9 = 400

t = 20s

in 20s the Horizontal distance traveled is ab

then

ab = Vx×t = 60×20 = 1200m


hope it will help you..