an aeroplane is flying horizontally with a velocity of 600kmph at a height of 1960m.when it is vertically above a point a on the ground,a bomb is released from it,the bomb strikes the point B find the distance AB
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see in the question its given:
Velocity= 600Km/hr = 600x1000/3600 m/s=166.66m/s
Ht=1960m.
To Find: The range of the projectile (R).
Its actually a Projetile motion .
For a projectile Ht=1/2*g*t*t.There fore we get t= 20s.
R=V*t=166.66*20=3333.33m/s=3.333Km/hr.
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