An aeroplane is flying horizontally with a velocity of 600 at a height of 1960
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Initial horizontal velocity , u= 699 km / h= 166.6m/s.Initial velocity = 0m/s
Let the time taken to reach the ground be t sec. Vertical distance covered h= 1960
h=1/2gt^2
t= root 2h/ g
Horizontal range AB= ut
=> u× root 2h/g
=> 166.67root 2×1960/9.8
=> 333.4m
=> 3.3km
Hope it will help you!☺
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