Question

An aeroplane is flying horizontally with a velocity of 600 km/h at a height of 1960 m. When it is vertically at a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

Answer 1

Answer:

Explanation: From h=12gt2

we have, tOB=2hOAg‾‾‾‾‾‾√=2×19609.8‾‾‾‾‾‾‾‾‾‾√=20s

Horizontal distance AB=vtOB

=(600×518m/s)(20s)

=3333.33m=3.33km.

Answer 2

Answer:

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Explanation:

see in the question its given:

Velocity= 600Km/hr = 600x1000/3600 m/s=166.66m/s

Ht=1960m.

To Find: The range of the projectile (R).

Its actually a Projetile motion .

For a projectile Ht=1/2*g*t*t.There fore we get t= 20s.

R=V*t=166.66*20=3333.33m/s=3.333Km/hr.