Question

An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. when it is vertically at a point a on the ground a bomb is released from it. the bomb strikes the ground at point



b. the distance ab is



a.1200 mb.0.33 kmc.3.33 kmd.33 km

Answer 1

initial velocity of bomb= 600 km/h in horizontal direction and 0 in vertical direction.
vertically it will cover 1960m=s
s=(1/2)*g*t^2
1960=1/2*10*t^2
1960=5*t^2
t^2=392
t=sqrt(392)=19.80s
similarly it will cover horizontal distance=d=166.67*19.80=3.33km
so c is the correct choice.

Answer 2

Answer:

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Explanation:

see in the question its given:

Velocity= 600Km/hr = 600x1000/3600 m/s=166.66m/s

Ht=1960m.

To Find: The range of the projectile (R).

Its actually a Projetile motion .

For a projectile Ht=1/2*g*t*t.There fore we get t= 20s.

R=V*t=166.66*20=3333.33m/s=3.333Km/hr.