Question

An aeroplane is flying in horizontal direction with a velocity of 600 km/h and at a height of 1960 m When it is vertically above a point A on the ground a body is dropped from it, the body strikes the ground at point B. Then, the distance AB will

Answer 1

Initial horizontal velocity, u = 600 km/h = 166.6 m/s

Initial vertical velocity = 0 m/s

Let the time taken to reach the ground be t s.

Vertical distance covered, h = 1960 m



Horizontal range, AB

= ut

Answer 2

Answer:

Velocity of the aeroplane = 600 km/hr.

Height = 1960 m.

A body is dropped from the point vertically above point A, then the body strikes the point B.

We need to find the Distance AB.

We know that, h = ½gt².

So, t = √2h/g

⇒ t = √2(1960)/9.8

⇒ t = √(2×200)

⇒ t = √400

⇒ t = 20 s

Now, AB = vt

⇒ AB = (600×5/18)×20

⇒ AB = 3333.33 m

⇒ AB = 3.33 km

Hence, the Distance AB = 3.33 km.