An aeroplane is travelling horizontally at a height
of 2000 m from the ground. The aeroplane, when
at a point P, drops a bomb to hit a stationary target
Q on the ground. In order that the bomb hits the
target what angle A must the line PQ make with
the vertical? (g = 10 ms?)
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An aeroplane is travelling horizontally at a height
of 2000 m from the ground. The aeroplane, when
at a point P, drops a bomb to hit a stationary target Q on the ground.
To find : angle made by line PQ with the vertical when bomb hits the target.
solution : see figure, an aeroplane is travelling horizontally at a height h = 2000 m from the ground. a bomb is droped from the point P.
initial velocity of bomb , v = 0 m/s
using formula, h = ut + 1/2 at²
h = 2000 m , u = 0 , a = 10 m/s²
⇒2000 = 1/2 × 10 × t²
⇒2000 = 5t²
⇒t = 20 sec
horizontal distance covered by bomb, R = 100m/s × 20 sec
= 2000 m
tanA = R/h = 2000 m/2000 m = 1
⇒tanA = tan45°
⇒A = 45°
therefore angle made with vertical is 45°
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