an aeroplane lands on the Runway and a speed of 180 km per hour its brakes can get reduced iteration of 0.2 m square the time taken by to take rest
Answers
Answered by
1
Second Equation of motion can be used
v=ut + (1/2)at²
here v=0, u=180km/hr= 50 m/s, a=-0.2 m/s²
0=50t - (1/2)×0.2×t²
On Further solving this equation, we get
t= 500 seconds ANS...
v=ut + (1/2)at²
here v=0, u=180km/hr= 50 m/s, a=-0.2 m/s²
0=50t - (1/2)×0.2×t²
On Further solving this equation, we get
t= 500 seconds ANS...
Similar questions