Question

an aeroplane lands with a velocity of 270 km h -1 and comes to rest after coming here and way of 1000 m the time in which aeroplane come to rest is with full answer

Answer 1

$u = 270km \: per \: hour \\ \: \: \: = \frac{270 \times 1000}{60 \times 6 } \\ \: \: \: \: \: = 75m \: per \: second \\ v = 0 \\ s = 1000m \\ {v}^{2} = {u}^{2} + 2as \\ {0}^{2} = {75}^{2} + 2 \times a \times 1000 \\ 2000a = - 5625 \\ a = 2.8125 \\ now \\ v = u + at \\ 0 = 75 + 2.8125t \\ t = 75 \div 2.8125 \\ t = 26.27s$
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