Question

An aeroplane lands with a velocity of 270 km/h and come to rest after covering a run way of 1000m. the time in which aeroplane come to rest is

Answer 1

Using Newton's second equation

v^2-u^2=2as

Given: S=1000m

u=270km/h = 75m/sec

v=0

Substituting the values

Answer: a= -2.8125

Now using Newton's first law

v-u=at

Answer: 34.3249 sec = t

Answer 2

by using v²-u²=2as

here u=270km/hr=75m/s,distance is 1000m

v=0m/s

0-(75)²=2000a

-5625=2000a

a=-5625/2000

a=-2.8125m/s²

by using v=u+at

0=75+(-2.8125×t)

t=-75/-2.8125

t=26.6667