Question

An aeroplane lands with a velocity of 270kmh and come to rest, after covering a run
way of 1000m. The time in which aeroplane come to rest is -
A) 26.67s
B) 16.67 c) 6.67s D) 62.67s​

Answer 1

Answer:

26.67s

Explanation:

u = 270kmph = 270 × 5/18

= 75 m/s

v = 0

s = 1000

a = ?

v2 - u2 = 2as

v2 - u2 / 2s = a

- 75 ^ 2 / 2×1000 = a

5625 / 2000 = a

a = 2.8125

We found out a so we can find out time now

a = v - u / t

t = v - u / a

= -75 / 2.8125

= 26.67 s

Answer 2

Answer:

b. 16.67

is your right answerl