An aeroplane leaves an airport and flies due north at a speed of 1000 km per hour. At the same time, another aeroplane leaves the same airport and flies due west at a speed of 1200 km per hour. How far apart will be the two planes after 1.5 hours?
NCERT Class X
Mathematics - Mathematics
Chapter _Triangles
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Answered by
205
Distance covered by the first plane in 1.5 hours = 1500 km
Distance covered by the second plane in 1.5 hours = 1800 km
The position of the two planes after 1.5 hour journey can be shown by a right triangle and we need to find the hypotenuse to know the aerial distance between them.
Here; h = ? p = 1800 km and b = 1500 km
From Pythagoras theorem;
h2 = p2 + b2Or, h2 = 18002 + 15002= 3240000 + 2250000 = 5490000Or, h = 300√61 km
Distance covered by the second plane in 1.5 hours = 1800 km
The position of the two planes after 1.5 hour journey can be shown by a right triangle and we need to find the hypotenuse to know the aerial distance between them.
Here; h = ? p = 1800 km and b = 1500 km
From Pythagoras theorem;
h2 = p2 + b2Or, h2 = 18002 + 15002= 3240000 + 2250000 = 5490000Or, h = 300√61 km
Answered by
117
by phythagorus theorem
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