An aeroplane leaves an airport and flies due north at a speed of 1000 km per hour. At the
same time, another aeroplane leaves the same airport and flies due west at a speed of
1200 km per hour. How far apart will be the two planes after
3/2 hours??
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Step-by-step explanation:
The first aeroplane leaves an airport and flies due north at a speed of 1000 km per hr.
∴ Distance travelled in 1.5 hrs.
=1000×1.5=1500 km
Similarly, Distance traveled by second aeroplane,
=1200×1.5=1800 km
In △ABC,
BC is distance travelled by first aeroplane and BA is the distance traveled by second aeroplane.
Hence, applying Pythagoras Theorem,
AC
2
=AB
2
+BC
2
∴ AC
2
=1500
2
+1800
2
∴ AC=300
61
km
Hence, two planes are 300
61
km apart.
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