An aeroplane leaves an airport and flies due north at a speed of 1000km/h .At the same time, another aeroplane leaves the same airport and flies due West at a speed of 1200km/h. How far apart will be the two planes after 1 1/2 h?
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1
Step-by-step explanation:
The first aeroplane leaves an airport and flies due north at a speed of 10 km per hr.
∴ Distance travelled in 1. hrs.
=100×1.=150 km
Similarly, Distance traveled by second aeroplane,
=120×1.=180 km
In △ABC,
BC is distance travelled by first aeroplane and BA is the distance traveled by second aeroplane.
Hence, applying Pythagoras Theorem,
AC
2
=AB
2
+BC
2
∴ AC
2
=1500
2
+1800
2
∴ A=300
61
km
Hence, two planes are 300
61
km apart.
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3
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