Question

An aeroplane leaves an airport and flies due to net north at 300 kilometre per hour at the same time another aeroplane leaves the same airport and flies due west at 400 km per hour how far apart are the aeroplanes in 1 and a half hours

Answer 1

Answer: 750 km

Step-by-step explanation:

speed of north flying aeroplane=300 km/hr

speed of west flying aeroplane=400 km/hr

let distance of north flying aeroplane be 'a'(BC=a

distance of west  flying aeroplane be 'b'(AC=b)

time given= 1 1/2 hr

as plane are travelling north and west resp.

∴∠B=90

so distance b/w plane is AB=c

also ac²= bc²+ ab²

and, speed = distance/ time

therefore distance= speed *time

in the case of north flying plane

a=300*1.5

a= 450 km

in the case of west  flying plane

b= 400*1.5

b=600 km

now using pythagoras theorem

a²+b²=c²

c²= 600²+450²

c²=360000+202500

c=$\sqrt{562500}$

c=750 km

therefore distance b/w  the 2 planes is 750 km

hope it helps