An aeroplane left 50 minutes later than its scheduled time and in order to reach the destination 1250 km away it had to increase its speed by 250km/hr from its usual speed. Find its usual speed.
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Let the usual speed be x km/hr
Case 1 : speed is x km/hr
∵speed = distance/time
∴time = distance/ speed
⇒ t = 1500/x ............................1)
Case 2 : speed is x + 250 km/hr
∵speed = distance/time
∴ t= 1500/x+250 .......................................2)
∴ from case 1 and 2 we have
1500/x - 1500/x+250 = 50/60 .......(∵ plane is 50 mins late)
⇒2250000 = 5xsquare + 1250x
⇒xsquare +750x + 750000 = 0
⇒x = 500 or x=-750
∵speed can't be negative
∴x =500 km/hr
Case 1 : speed is x km/hr
∵speed = distance/time
∴time = distance/ speed
⇒ t = 1500/x ............................1)
Case 2 : speed is x + 250 km/hr
∵speed = distance/time
∴ t= 1500/x+250 .......................................2)
∴ from case 1 and 2 we have
1500/x - 1500/x+250 = 50/60 .......(∵ plane is 50 mins late)
⇒2250000 = 5xsquare + 1250x
⇒xsquare +750x + 750000 = 0
⇒x = 500 or x=-750
∵speed can't be negative
∴x =500 km/hr
Phillipe:
brainliest plz
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