An aeroplane moves 400m towars north 300m towards west and then 1.2 km vertically upwards. Then it's displacement from inital position is_________.Explain your answer.
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The plane started from point A, and it moved 400m in the north to point B, after that it turned left and moved 300 m in the West towards C.
This has formed a right angled triangle ABC. Where B=90° and AC is hypotenuse. By the pythagorian theorem we can see that the length AC is 500 m. Now the plane moves vertically upward 1200 m up to another point. So there is another right angled triangle ACD with AD as the hypotenuse.
And thus AD comes out to be 1300 m.
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