Question

An aeroplane moves with a horizontal velocity u. It drops a bomb from a height h. Then the time t taken by the bomb in reaching the ground will be equal to

Answer 1

it is equal to time by gravity
hence
h=1/2×g×t^2
t=
$\sqrt{ \frac{2h}{g} }$

Answer 2

Initially the pocket has only horizontal velocity equal to u

When it reaches the ground it has horizontal velocity u and vertical velocity √2gh

Therefore resultant velocity =√u2+2gh

...........

use v = u+ gt

then you find the value of

t = ?????