Question

An aeroplane moving horizontally with 50 metre per second drop a packet at 490 metre height what is its time of flight?????

Answer 1

Answer:

Is the answer 14 under root 5

Answer 2

Answer:

T=10 s

Explanation:

H = 490 m

V= 50 m/s

$t = \sqrt{ \frac{2h}{g} } = \sqrt{ \frac{2 \times 490}{9.8} } = 10 \: s$