Question

An aeroplane moving horizontally with a speed of 720
km/h drops a food pocket, while flying at a height of
396.9 m. the time taken by a food pocket to reach the
ground and its horizontal range is (Take g=9.8 m/sec)
(1) 3 sec and 2000 m
(2) 5 sec and 500 m
(3) 8 sec and 1500 m
(4) 9 sec and 1800 m​

Answer 1

Answer:

4) 9sec and 1800m

Explanation:

in figure

Answer 2

Answer:

As the packet simply gets dropped, it's initial vertical velocity u = 0

Time taken for the packet to reach ground is

T =√(2H/g) = √(2*396.9/9.8) = √81 = 9s

Horizontally the packet travels at the speed of aeroplane,

V = 720kmph = 720*(5/18) = 200m/s

Range R = V*T = 200*9 = 1800m

Ans : Option 4