Question

An aeroplane moving horizontally with an speed of 180km/hr. drops a food packet while flying at a height of 490m. The horizontal range of the packet is

Answer 1

see ...this..I solve this......

Answer 2

The horizontal range is 500 m

Given:

Speed of aeroplane = 180 km/hr

Height = h = 490 m  

Solution:

The velocity is converted from km/hr to m/s,

$180 \left( \frac{1000}{3600} \right) =50 \ \mathrm{m} / \mathrm{s}$

Time taken to reach ground is given by the formula:

$\text{Time \ of \ flight}, \ T=\sqrt{\frac{2 h}{g}}$

$T=\sqrt{\frac{(2 \times 490)}{9.8}}$

$T=\sqrt{\frac{980}{9.8}}$

$T=\sqrt{100}$

T = 10 seconds

Therefore, the horizontal range is given by the formula below:

$R=\text { Horizontal distance } \times \text { Time }$

$R=u \times T$

$\Rightarrow R=50 \times 10$

$\therefore R=500 \ m$