An aeroplane of mass 2.5 x 10^5 kg lands with a speed of 62 m/s, on a horizontal runway at time t = 0. The aeroplane decelerates uniformly as it travels along the runway in a straight line until it reaches a speed of 6.0 m/s at t = 35 s. Calculate the resultant force acting on the aeroplane as it decelerates.
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a = \frac{1.6m}{ {s}^{2} }a=
s
2
1.6m
Explanation:
Accelerated Motion
It occurs when an object changes its speed over time. If the changes in speed are uniform, then the acceleration is constant, positive if the speed increases, negative if the speed decreases.
The acceleration is calculated as follows:
a = uf - uoa=uf−uo
a = \frac{6 - 62}{35} = - \frac{56}{35}a=
35
6−62
=−
35
56
a = - 1.6m {s}^{2}a=−1.6ms
2
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