Physics, asked by basheerpasha61974, 10 months ago

An aeroplane of mass 400 ton is moving with a speed of 450 kmph of a height of 500 m from the ground Its potential energy is ​

Answers

Answered by sunnyk1572
6

Answer:

2×10^6

Explanation:

m=400ton=400×10^3 kg

v=450 kmph=450×5/18

v=125m/s

h=500m

P=mgh

P=400×10×500

P=2000000

P=2×10^6 J

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