An aeroplane of mass 400 ton is moving with a speed of 450 kmph of a height of 500 m from the ground Its potential energy is
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Answer:
2×10^6
Explanation:
m=400ton=400×10^3 kg
v=450 kmph=450×5/18
v=125m/s
h=500m
P=mgh
P=400×10×500
P=2000000
P=2×10^6 J
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