Question

an aeroplane on a Runway start from rest and pics of a velocity of 180 km per hour and it takes off in doing so it covers a Runway of 1.5 km calculate the information acting on the aeroplane and the time in which it takes off

Answer 1

Hii..
Here is your answer..

Solution:-
Initial velocity=0
Final velocity=180km
Distance=1.5km

We'll first find the Acceleration by using equation:-
$= > {v}^{2} = {u}^{2} + 2as\\ = > {(180)}^{2} = {(0)}^{2} + 2 \times a \times 1.5 \\ = > 32400 = 3a$
$= > a = \frac{32400}{3} \\ = > a = 10800km \: per \: hrs \: sq.$
Now,
We'll find the Time by using equation:-
$= > v = u + at \\ = > 180 = 0 + 10800 \times t \\ = > 180 = 10800t \\ = > t = \frac{10800}{180}$
$= > t = 60hrs$
Hope it helps uh...✌️✌️✌️