Question

An aeroplane on a runway starts from rest and picks up a velocity of 180km/h and takes off . In doing so it covers a runway of 1.5km calculate
(a) the uniform acceleration acting on the aeroplane and
(b) the time in which it takes off

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Answer 1

First, we will convert all units to a simpler form
(180*1000)m/(1*60*60)sec = 50 m/s
1.5 km = 1500 m
D = 1500 m
v(Final velocity) = 50 m/s
u(Initial Velocity) = 0 (Given)

[B]
Velocity(V) = Distance Covered(D) / Time taken(T)
So ,      T = D/V
T = 1500/50 = 30 seconds

[A]
Acceleration = (v-u)/t
                     = (50-0)/30
                     = 5/3 m/s^2

Answer 2

Answer:

25m/s^2

Explanation:

1800×5/18 = 500m/s

v^2= u^2 +2as

(500)^2= 0 + 2×a×5000

a= 25m/s^2