Question

An aeroplane runs 5km.to east then 5km.to north on a plane then flies to an angle 30° with horizontal to a distance 5km.in 30 secs. Find out the average speedand average velocity of the aeroplane ?​

Answer 1

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Answer 2

Answer:

vx = v cos θ

vy = v sin θ

\displaystyle v=\sqrt{{{v}_{x}}^{2}+{{v}_{y}}^{2}}v=√

v

x

2

+v

y

2

θ = tan − 1 (vy /vx).

The figure shows components of velocity v in horizontal x axis v x and in vertical y axis v y. The angle between the velocity vector v and the horizontal axis is theta.

Explanation:

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