An aeroplane starts from rest with an acceleration of 3ms-2 and takes a run for 35 s before taking off. What is minimum length of the runway and with what velocity the plane took off?
Answers
Answered by
178
s = ut+1/2at^2
s = 0 + 1/2 * 3 * 35 * 35
s = 1837.5m
v = u + at
= 0 + 3 * 35
= 105 m/s.
Hope this helps!
s = 0 + 1/2 * 3 * 35 * 35
s = 1837.5m
v = u + at
= 0 + 3 * 35
= 105 m/s.
Hope this helps!
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Answered by
40
Given that,
Initial speed of an aeroplane, u = 0
Acceleration of the aeroplane,
Time, t = 35 s
To find,
The minimum length of the runway and with what velocity the plane took off.
Solution,
The minimum length of the runway means we need to find the distance covered. So,
u = 0
Let v is the took off velocity. So,
Hence, this is the required solution.
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