An aeroplane starts from rest with an acceslaration of 3m/s and takes a run for 35s before taking off. what is the minimum length of runway and with velocity the plane took off
Answers
Answered by
0
length of plane=1837.5
use s=ut+1/2at*t
u=0,a=3,t=35
find s ...and thats the answer
Answered by
1
Answer:
Explanation:
given
t=35 sec
a=3m/s2
=u=0
=s= ut+1/2at2
=s=0*t+1/2*3*35*35
=s=3*35*35 upon 2
=3675/2
=1837.5
Let v is the took off velocity so,
v=u+at
v = 0+3*35
v=105 m/s
Similar questions