An aeroplane takes 1 hr less for a journey of 1200km if its original speed is increased by 100kmhr from its usual speed. Find its usual speed.
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Let original speed be x.
time = distance/speed
original time = 1200 / x
new time = 1200 / x+100
1200 / x - 1200 / x + 100 = 1
1200 (1 / x - 1 / x + 100)=1
1200 (x + 100 - x / x* +100x) =1
here x* is x square.
120000 = x * + 100x
x * + 100x -120000 =0
therefore by solving equation
x = 300 km/hr
seee... hope it help's uu
Let original speed be x.
time = distance/speed
original time = 1200 / x
new time = 1200 / x+100
1200 / x - 1200 / x + 100 = 1
1200 (1 / x - 1 / x + 100)=1
1200 (x + 100 - x / x* +100x) =1
here x* is x square.
120000 = x * + 100x
x * + 100x -120000 =0
therefore by solving equation
x = 300 km/hr
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