Question

An aeroplane takes 3 hours to fly 1200 km against the wind. The return trip takes 2 hours. Find the speed of the plane in still air and the wind speed.

(it's a simultaneous linear equation so the answer is not 400km/h) Please solve with solution and do not spam. I'll mark you brainliest if u provide answer with steps) ​

Answer 1

Let the speed of airplane in steel air and wind are  

a  and  w

miles/hour respectively. Then for onward trip the net speed is

( a − w ) miles/hour and for return trip the net speed is

( a + w )  miles/hour.

For onward trip  ( a − w ) ⋅ 3 = 1200 or a − w = 400 ( 1 )

For return trip  ( a + w ) ⋅ 2 = 1200 or a + w = 600 ( 2 )

Adding equation  ( 1 ) and ( 2 ) ,we get  

2 a = 1000  or  a = 500

From equation  ( 1 )

∴ w = a − 400

∴ w = 500 − 400 = 100

The speed of airplane in steel air and wind are  500 and 100  miles/hour respectively.