Question

an aeroplane takes off from a field has a run of 500 m. what is the acceleration and take off velocity if it leaves the ground 10s aftrr the start

Answer 1

hope this helps you !!!!

Answer 2

Given:
DISTANCE = s=500m
Initial velocity =u=0 m/s
Final velocity =V=?
Time=t=10s
From Second equation of motion:
S=ut + 1/2at^2
500=0*10 +1/2 *a 100
a=500/50=10m/s2
From V= u+ at
=0+10*10
=100m/ s
Therefore , acceleration is 10m/ s2 and take off velocity is 100m/s.