Question

an aeroplane takes off ground after covering a length of 800m of Runway in 16 seconds find its acceleration and velocity of take off

Answer 1

u=0m/s(aeroplane takes off)
v=???(to be calculated)
s=800m
t=16s
a=???(to be calculated)
$s = ut + \frac{1}{2} at {}^{2} \\ 800 = 0 \times 16 + \frac{1}{2} \times a \times 16 \times 16 \\ 800 = 0 + 128a \\ a = \frac{800}{128} = 6.25 \: mps {}^{2}$
$v = u + at \\ = 0 + 6.25 \times 16 \\ = 100mph$
So, acceleration is 6.25m/s^2.
velocity is 100m/s.

Answer 2

U=0m/s
V=?
S=800m
T=16s
A=?
S=ut+1/2 at^2
800=0*16+1/2 *a*16*16
800=0+128a
A=800/128=6.25m/s^2
Therefore, acceleration =6.25m/s^2
V=u+at
V=0+6.25*16
Therefore, v=100m/s