an Aeroplane taking off from a field has a run of 500 m.what is the acceleration and take of velocity if it leaves the ground 10 sec after the start?
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Use the 2nd equation of 1D kinematics(s=ut+1/2at^2).
Detailed solution is in the attachment.
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Detailed solution is in the attachment.
If you found it useful then please mark it as the brainliest.
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distance (s) = 500m
initial velocity (u) = 0m/s
time = 10sec
using second equation of motion
s = ut +1/2at²
500 = (0)(10)+1/2(a)(10)²
500 = 0+(100a)/2
500 = 50a => a = 500/50 = 10m/s²
using first equation of motion
v = u+at
v= 0+(10)(10) => v = 100m/s
hope this helps
initial velocity (u) = 0m/s
time = 10sec
using second equation of motion
s = ut +1/2at²
500 = (0)(10)+1/2(a)(10)²
500 = 0+(100a)/2
500 = 50a => a = 500/50 = 10m/s²
using first equation of motion
v = u+at
v= 0+(10)(10) => v = 100m/s
hope this helps
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