An aeroplane taking off from a field has a run of 500 m . What is the acceleration and take off velocity if it leaves the ground 10 seconds after the start ?
Answers
QueStI0N -
An aeroplane taking off from a field has a run of 500 m .
What is the acceleration and take off velocity if it leaves the ground 10 seconds after the start ?
SoLuTiOn -
In the above Question , the following information is given -
The length of the runway is 500 m .
The aeroplane leaves the ground 10 seconds after the start .
So,
The speed of the aeroplane while on the ground -
=> ( 500 m / 10 s ) = 50 m/s .
Now, Let us find the acceleration of the plane .
According to the Second Equation Of Motion -
S = ut + ( 1/2 ) at^2 .
The plane is innitially at rest.
So, u = 0
=> 500 = ( 1 / 2 ) × a × 100
=> Acceleration = 10 m/s .
Now according to the First Equation Of Motion -
v = u + at
=> v = 0 + 100
=> v = 100 m/s.
So, the required velocity of the plane when it just leaves the ground is 100 m/s .
GiveN :-
♦ Distance travelled, s = 500 m
♦ Initial velocity, u = 0 m/s 〘As the aeroplane starts from rest〙
♦ Time, t = 10 s
TO FinD :-
The acceleration and the take off velocity of the aeroplane.
AcknowledgemenT :-
♦ s = ut + 1/2 at²
- s is the distance travelled.
- u is the initial velocity
- t is the time taken
- a is the acceleration
♦ v = u + at
- v is the final velocity.
- u is the initial velocity
- a is the acceleration
- t is the time taken
SolutioN :-
Therefore, the acceleration and the take off velocity of the aeroplane are 10 m/s² and 100 m/s respectively.