Question

an aeroplane taking taking off from a field has a run of 500 m. what is the acceleration and take off velocity if it leaves the the ground 10 seconds after the start?

Answer 1

u=0m/s(body starts from rest)
s=500m
v=???(to be calculated)
t=10 seconds
a=???(to be calculated)
$s = ut + \frac{1}{2}at {}^{2} \\ 500 = 0 \times 10 + \frac{1}{2} \times a \times 10 \times 10 \\ 500 = 0 + 50a \\ a = \frac{500}{50} = 10$
a=10m/s^2
$v = u + at \\ = 0 + 10 \times 10 \\ = 100$
v=100m/s

So, acceleration is 10m/s^2
and final velocity is 100m/s.