Question

An aeroplane taxi on the runway for 30 metres and acceleration of 3.2 metre per second square before takeoff in how much days and would have cover on runway?

Answer 1

Answer: Initial speed of airplane  u=0 m/s

Acceleration of the plane  a=3.2 m/s  

2

 and time taken t=3.28 s

Using formula, distance covered S=ut+  

2

1

​  

at  

2

   

⇒   S=0(32.8)+0.5(3.2)(32.8)  

2

=1721.3∼1720m

Explanation:if this is correct mark me as brainliest

Answer 2

Answer:

The aeroplane would have covered 1440 m distance.

Explanation:

a = 3.2 m/s²

t = 30 s

u = 0 m/s

s = ut + ½ at²

=> s = 0 * 30 + ½ * 3.2 * 30²

=> s = 0 + ½ * 3.2 * 900

=> s = ½ * 900 * 3.2

=> s = 450 * 3.2

=> s = 1440 m

The aeroplane would have covered 1440 m distance.