Question

an aeroplane touches down at 225 km/h and stops after 2 mins . Calculate the accelerator length of runway

Answer 1

See the initial velocity(u) of the aeroplane will be 216 km/h = 60 m/s

Final velocity (v) = 0 m/s

And displacement till it comes to rest is 2000m

So by using formula

V^2 - U^2 = 2as

0 - 3600 = 2a(2000)

Hence a = - 0.9 m/s^2

So by using formula v-u=at

We get 0–60 =- 0.9t

Hence t is approximately 66.67 seconds

Hope this will help