Question

An aeroplane touches down ( land) at a speed of 180 km/h and stop after covering a runway of 1 km. Calculate ( I) the retardation. And (ii) the time in which the plane comes to rest 1 ( i) 1 . 25 m/ s2 ( ii) 40 s/

Answer 1

Explanation:where, v = final velocity of the aeroplane, u = initial velocity of the aeroplane, a = retardation, S = distance, t = time. Thus the retardation of the aeroplane is 16200 km/hr². Thus, the time required for the aeroplane to stop is 1/90 hr. 1/90 hr = (1 x 3600)/90 sec = 40 sec.

Answer 2

Answer:  RETARDATION IS 4500 M/S AND TIME TAKEN IS

39.996s round of is 40s

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