Question

An aeroplane travel a journey in 9 hrs with the speed of 1260 km/h. to complete the journey in 5 hrs. find the increased speed to cover the distance ​

Answer 1

Distance = (240 × 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr. [We can write 1

3

2

hours as 5/3 hours]

∴ Required speed = (1200×

5

3

) km/hr=720 km/hr.

Answer 2

$\color{grey}\underline{ \rm \large \: \:Question :- }$

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An aeroplane travel a journey in 9 hrs with the speed of 1260 km/h. to complete the journey in 5 hrs ; find the increased speed to cover the distance

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$\color{grey}\underline{ \rm \large \: \: Given :- }$

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•Time taken by An aeroplane travel a journey = 9 hrs

• Speed of aeroplane = 1260 km/h.

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$\color{grey}\underline{ \rm \large \: \: To \: Find :- }$

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• The increased speed to cover the distance to complete the journey in 5 hrs

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$\color{grey}\underline{ \rm \large \: \: Formula \: Used:- }$

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$\: \: \: \: \: \: \sf \star \: \: Speed = \dfrac{Distance}{Time}$

$\: \: \: \: \: \: \sf \star \: \:Distance = Speed \times Time$

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$\color{grey}\underline{ \rm \large \: \: Step \: By \: Step \: Solution:- }$

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Now , We know that ,

• Speed = 1260 km/hrs
• Time = 9 hrs

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$\: \: \: \: \: \: \sf :\Longrightarrow \: \:Distance = Speed \times Time$

$\: \: \: \: \: \: \sf :\Longrightarrow \: \:Distance = 1260 \times 9$

$\: \: \: \: \: \: \sf :\Longrightarrow \: \:Distance = 11340 km$

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Now , Distance travelled by An aeroplane to travel a journey in 9 hrs with the speed of 1260 km/h is 11340 km

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So , we know the distance .. now , let's Find the increased speed to cover the distance to complete the journey in 5 hrs

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• Distance = 11340 km
• Time = 5 hrs

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$\: \: \: \: \: \: \sf :\Longrightarrow \: \: Speed = \dfrac{Distance}{Time}$

$\: \: \: \: \: \: \sf :\Longrightarrow \: \: Speed = \dfrac{11340 }{5}$

$\: \: \: \: \: \: \sf :\Longrightarrow \: \: Speed = \green{2268 \: km/hr}$

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$\color{grey}\underline{ \rm \large \: \: Answer:- }$

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Required speed = 2268 km/hr