An aeroplane travels a distance of 2400km with certain speed. While returning, its speed gets reduced by 50 km/hr and it reaches 12 minutes late. find the speed of plane
Answers
The speed of the plane is 799.19 m/s.
Step-by-step explanation:
Distance travelled by plane = 2400 Km
Let speed be = x Km/h
Time taken = 2400 / x
Time taken in returning = 2400 / x - 50
According to the statement of the question.
2400/x = 2400 / x - 50 + 1/5
2400 / x = 12000 + x -50 / 5 ( x - 50)
12000 x - 600000 = 1115 ox + r^2
50x - 600000 = x^2
x^2 - 50 x + 60000 = 0
x = -b ± √ b^2 - 4 ac / 2a
x = 50 ± √ (50)^2 - 4 x 1 x 60000 / 2
x = 50 ± √ 2500 - 2400000 / 2
x = 50 ± √ - 2397500 / 2
x =50 + 154038 / 2
x = 1598.38 / 2
x = 799. 19 m/s
Thus the speed of the plane is 799.19 m/s
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