Question

An aeroplane travels distance 2500 km and 500 km at the rate of 500 km /hr , 400 km/hr and 250 km/hr respectively . the average speed of the plane is

Answer 1

time = distance/speed
time = 2500/500 + 1200/400 + 500/250
        = 5+3+2=10 hrs

speed = total distance/time
           = (2500+1200+500)/10
           = 4200/10
           = 420 km/h

i hope it will help you
regards

Answer 2

Answer:

Answer:

${\large{\boxed{\colorbox{lime}{\pink{\text{QUESTION}}}}}}$

an Aeroplane covers 2500km, 1200km,and 500km at the rate of 500 km/hr, 400km/hr and 250km/hr respectively. find its average speed.

${\large{\boxed{\colorbox{lime}{\pink{\text{answer}}}}}}$

$\sf{\bold{\red{ distance=500km}}}$

speed=500km/hr

$\sf{\bold{\blue{time \: taken \: to \: cover \: 2500 \: km:}}}$

$\frac{2500}{500} = 5hrs$

$\sf{\bold{\green{distance=1200km}}}$

$\sf{\bold{time: 400km/hr}}$

$\sf{\bold{\red{ time \: taken = }}}$

$\frac{1200}{400} = 3hr$

$\sf{\bold{\orange{distance=500}}}$

$\sf{\bold{\blue{speed=250km/hr}}}$

$\sf{\bold{\green{time \: taken=}}}$

$\frac{500}{250}= 2hr$

$\sf{\bold{\red{total \: distance = }}}$

$2500 + 1200 + 500 = \: 4200km$

$\sf{\bold{\orange{total \: time \: taken = }}}$

$5 + 3 + 2 = 10$

$\sf{\bold{\blue{average \: speed=}}}$

$\sf{\bold{\green{ \frac{4200}{10} = }}}$

${\large{\boxed{\colorbox{lime}{\pink{\text{420km/hr}}}}}}$